Two point charges, Q 1 = 3.6 C and Q 2 = -1.7 C , are placed on the x axis. Supp

Question

Two point charges, Q1 = 3.6 C and Q2 = -1.7 C , are placed on the x axis. Suppose that Q2 is placed at the origin, and Q1 is placed at the coordinate x1 = 5.0 cm (Figure 1) .

Part A

At what point(s) along the x axis is the electric field zero? Determine the x-coordinate(s) of the point(s).

Express your answer using two significant figures. If there is more than one answer, enter your answers in ascending order separated by commas.

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Part B

At what point(s) along the x axis is the potential zero? Determine the x-coordinate(s) of the point(s).

Express your answer using two significant figures. If there is more than one answer, enter your answers in ascending order separated by commas.

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Figure 1 of 1

Two point charges, Q1 = 3.6 C and Q2 = -1.7 C , are placed on the x axis. Suppose that Q2 is placed at the origin, and Q1 is placed at the coordinate x1 = 5.0 cm (Figure 1) .

Part A

At what point(s) along the x axis is the electric field zero? Determine the x-coordinate(s) of the point(s).

Express your answer using two significant figures. If there is more than one answer, enter your answers in ascending order separated by commas.

xE =   cm  

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Incorrect; Try Again; 6 attempts remaining

Part B

At what point(s) along the x axis is the potential zero? Determine the x-coordinate(s) of the point(s).

Express your answer using two significant figures. If there is more than one answer, enter your answers in ascending order separated by commas.

xV =   cm  

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Figure 1 of 1

Explanation / Answer

The electric field is a component of the electromagnetic field.
Electric fields satisfy the superposition principle. As a result, if E1 and E2 are the electric fields resulting from distribution of charges Q1 and Q2 a distribution of charges Q1 + Q2 will create an electric field E1 + E2
Let the point be x at which field will be zero
E=kQ1/(x-x1)^2 + kQ2/(x-0)^2 = 0
=> Q1x^2 = Q2(x-x1)^2
=> x1= -0.23 cm

Let y be the point at which potential is zero

Then, kQ1/(y-x1) = kQ2/y

=> y = -0.44 cm

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