A rotating space station is said to create \"artificial gravity\"—a loosely-defi

Question

A rotating space station is said to create "artificial gravity"—a loosely-defined term used for an acceleration that would be crudely similar to gravity. The outer wall of the rotating space station would become a floor for the astronauts, and centripetal acceleration supplied by the floor would allow astronauts to exercise and maintain muscle and bone strength more naturally than in non-rotating space environments. If the space station is 210 m in diameter, what angular velocity would produce an "artificial gravity" of 9.80 m/s2 at the rim? I can calculate Ar, but my calculator is not receiving the same answer when converting to rpm. I am typing (.306)(60/1)(1/2pi). Any help on that too?

Explanation / Answer

angular acceleratiom=w^2*radius

where w is angular velocity

9.8=w^2*(210/2)

w=0.305 radian per second

in rpm =(w/2pi)*60=2.91 rpm

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