Two long, straight wires cross each other at right angles, as shown in the figur

ID: 584271 • Letter: T

Question

Two long, straight wires cross each other at right angles, as shown in the figure below. (Assume I1 = 4.90 A and I2 = 2.72 A.)

(a) Find the direction and magnitude of the magnetic field at point P, which is in the same plane as the two wires.

(b) Find the magnetic field at a point 30.0 cm above the point of intersection (30.0 cm out of the page, toward you).

° counterclockwise from the +x-axis, parallel to the xy-plane

magnitude ? T direction ? out of the page into the page The magnitude is zero.

I1 = 4.9 A

I2 = 2.72 A

as the magnetic field due to a straight wire is given as

B = u0 *I/(2 *pi*d)

for the net field at point P

BP = u0 * I1/(2pi * 0.40) - u0 * I2/(2pi * 0.30)

BP = 4pi *10^-7/(2pi) * (4.90/0.40 - 2.72/.30)

BP = 6.37 *10^-7 T

the magnetic field at P is 6.37 *10^-7 T out of the page.

part B)

magnetic field due to I1

B1 = 4pi *10^-7 * 4.90/(2pi * 0.30) (-j)

B1 = -3.27 *10^-6 j T

magnetic field due to I2

B2 = 4pi *10^-7 * 2.72/(2pi * 0.30) (i)

B2= 1.81 *10^-6 i T'

magnitude of net field = sqrt(3.27^2 + 1.81^2) uT

magnitude of net field = 3.74 uT

the magnitude of net field is 3.74 uT

direction = 360 - arctan(3.27/1.81)

direction = 299 degree

the direction of net field is 299 degree

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