Two long, parallel wires are separated by a distance of 0.400 m. The currents I

Question

Two long, parallel wires are separated by a distance of 0.400 m. The currents I1 and I2 have the directions shown.

(a) Calculate the magnitude of the force exerted by each wire on a 1.2 m length of the other.
(b) Each current is halved, so that I1 becomes 2.50 A and I2 becomes 1.00 A. Now what is the magnitude of the force that each wire exerts on a 1.2 m length of the other?

Two long, parallel wires are separated by a distance of 0.400 m. The currents I1 and I2 have the directions shown. (a) Calculate the magnitude of the force exerted by each wire on a 1.2 m length of the other. (b) Each current is halved, so that I1 becomes 2.50 A and I2 becomes 1.00 A. Now what is the magnitude of the force that each wire exerts on a 1.2 m length of the other?

Explanation / Answer

A) force on each wire is F = 2 x10^-7 i1 i2 / l = 4*3.14*10^-7*5*2 / 2*3.14*1.2 = 2.36 x10^-5 N

because of opposite currents in the wire, the wires will repel each other

C) when both the currents are each half, the force will be come 1/4 times, so the new force will be

F' = F/4 = 2.36*10^-5 /4 = 5.9*10^-6 N

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