Two long thin parallel wires 15.0 cm apart carry 21 A currents in the same direc

Question

Two long thin parallel wires 15.0 cm apart carry 21 A currents in the same directions. Determine the magnetic field vector at a point 12.0 cm from one wire and 4.0 cm from the other (see figure).

_______ T   
_______ degrees (counterclockwise from horizontal to the right)

So maybe I'll be more specific about my question, since the last answer was extremely confusing and complicated.
I understand that magnetic field at P from wire 1 B1=?I/(2?r) = ?*21/(2?*.12m) (Wire 1 is at bottom of picture) = 3.5e-5
I understand that magnetic field at P from wire 2 B2=?I/(2?r) = ?*21/(2?.04m) (Wire 2 is at top of picture) = 1.05e-4
I understand that both of these are magnitudes, and I need to break them into component form to add them.

I don't understand how to get the angles, convert these answers to component form, so I can add them and get the net B magnitude and angle.

Can someone please explain from there how to finish this problem?

Explanation / Answer

Firstly what is not clear?:
1. You request magnetic field strength which, in SI units, is H (in A/m) but your answer is B (flux density) in Tesla. B =

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