1) For mendzelles, a fictitious animal, red eyes (E) are dominant over white eye
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Question
1)For mendzelles, a fictitious animal, red eyes (E) are dominant over white eyes (e) and gray skin (S) is dominant over white skin (s). These two genes are found on the same chromosome. You start by crossing an individual who is homozygous dominant for both traits with an individual who is homozygous recessive for both traits. You can assume crossing over does not occur. What are the genotypic and phenotypic ratios of the F1 generation?
A. All have red eyes and gray skin. (EeSs)
B. All have white eyes and white skin. (eess)
C. 1 red eyes and gray skin (EeSs) : 1 white eyes and white skin (eess)
D. 1 red eyes and gray skin (EESS) : 1 White eyes and white skin (eess)
2)For mendzelles, a long tail is dominant (T) over a short tail (t) and gray wings are dominant (W) over white wings (w). You cross an individual that is heterozygous for both traits with an individual that is homozygous recessive for both traits. If these two traits are not linked, what are the expected genotypic and phenotypic ratios of the F1 generation?
A. Genotype: 1 TTWW : 1 TTww : 1 ttWW: 1 ttww Phenotype: 1 Long tail, gray wings : 1 Long tail, white wings : 1 short tail, gray wings : 1 short tail, white wings
B. Genotype: 1 Ttww : 1 ttWw Phenotype: 1 Long tail, white wings : 1 short tail, gray wings
C. Genotype: 1 TtWw : 1 ttww Phenotype: 1 Long tail, gray wings: 1 short tail, white wings
D. Genotype: 1 TtWw : 1 Ttww : 1 ttWw : 1 ttww Phenotype: 1 Long tail, gray wings : 1 Long tail, white wings : 1 short tail, gray wings : 1 short tail, white
3)For mendzelles, a long tail is dominant (T) over a short tail (t) and gray wings are dominant (W) over white wings (w). You cross an individual that is heterozygous for both traits with an individual that is homozygous recessive for both traits. If these two traits are linked with the dominant alleles on one of the homologous chromosomes and the recessive alleles found on the other. What are the expected genotypic and phenotypic ratios of the F1 generation?
A. Genotype: 1 TTWW : 1 TTww : 1 ttWW: 1 ttww Phenotype: 1 Long tail, gray wings : 1 Long tail, white wings : 1 short tail, gray wings : 1 short tail, white wings
B. Genotype: 1 Ttww : 1 ttWw Phenotype: 1 Long tail, white wings : 1 short tail, gray wings
C. Genotype: 1 TtWw : 1 ttww Phenotype: 1 Long tail, gray wings: 1 short tail, white wings
D. Genotype: 1 TtWw : 1 Ttww : 1 ttWw : 1 ttww Phenotype: 1 Long tail, gray wings : 1 Long tail, white wings : 1 short tail, gray wings : 1 short tail, white wings
4)For mendzelles, a long tail is dominant (T) over a short tail (t) and gray wings are dominant (W) over white wings (w). You cross an individual that is heterozygous for both traits with an individual that is homozygous recessive for both traits. The observed phenotypic ratio for the offspring of this mating is 96 long tail, gray wings: 94 short tail, white wings: 20 long tail, white wings: 18 short tail, gray wings. What inheritance pattern explains the observed phenotypic ratio?
A. Incomplete Dominance
B. Codominance
C. Linked genes with crossing over occuring.
D. Sex chromosomes
5) suppose you cross a mendzelle that has straight antennae (AA) with one that has curly antennae (aa). All of the offspring have wavy antennae (an intermediate phenotype). What inheritance patterns best explains the phenotype of the offspring?
A. Incomplete Dominance
B. Codominance
C. Crossing over of linked genes
D. Polygenic inheritance
6)In four-o'clocks, the allele for red flowers is incompletely dominant over the allele for white flowers, so heterozygotes have pink flowers. What ratios of flower colors would you expect among the offspring of the following crosses: Parents: pink X pink
A. 1 Red : 2 Pink : 1 white
B. 1 Red : 1 Pink
C. All Red
D. All Pink
E. 1 Pink : 1 white
7)You cross a black cat and a tan cat and the mating produced 8 kittens, each of which are a mixture of black and tan. What inheritance pattern best explains the phenotype of the kittens?
A. Incomplete Dominance
B. Codominance
C. Crossing over of linked genes
D. Polygenic inheritance
8)An ABO human blood type question. If a girl has blood type O, what is one possible genotype of her parents?
A. Father AA; Mother BB
B. Father AO; Mother AB
C. Father AA; Mother AO
D. Father BO; Mother AO
E. Father OO; Mother BB
9)Duchenne muscular dystrophy (DMD) is caused by a relatively rare X-linked recessive allele. It results in progressive muscular wasting and usually leads to death before the age of 20. What is the probability that the second son of a woman who is a carrier will have DMD?
A. 1/8
B. 1/4
C. 1/2
D. 3/4
E. 0
Explanation / Answer
1) Cross between homozygous dominant red eyes and gray skin with homozygous recessive white eyes and white skin result F1 offsprings in 1:1 ratio. Option C is correct.
2) Cross between long tail, gray wings and short tail white tail, when the genes are not linked, results in F 1 offspring with Genotype: 1 TtWw : 1 Ttww : 1 ttWw : 1 ttww Phenotype: 1 Long tail, gray wings : 1 Long tail, white wings : 1 short tail, gray wings : 1 short tail, white. Option D is correct.
3) Cross between long tail, gray wings and short tail white tail, when the genes are not linked, results in F 1 offspring with Genotype: 1 TtWw : 1 ttww Phenotype: 1 Long tail, gray wings: 1 short tail, white wings. Option C is correct.
4) For mendzelles, a long tail is dominant (T) over a short tail (t) and gray wings are dominant (W) over white wings (w). You cross an individual that is heterozygous for both traits with an individual that is homozygous recessive for both traits. The observed phenotypic ratio for the offspring of this mating is 96 long tail, gray wings: 94 short tail, white wings: 20 long tail, white wings: 18 short tail, gray wings. The inheriatence pattern for phenotypic ratios observed is codominance. Option B is correct.
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