two neutral thick flat pieces of metal conductors are placed on each side of a t

Question

two neutral thick flat pieces of metal conductors are placed on each side of a thin sheet insulator with uniformly distributed positive charge. The surface charge density on the thin sheet is +2.5e-3 C/m2

1) calculate the electric field immediately above or below the thin sheet

2) indicate the direction of the electric field in the region just above the thin sheet with an arrow

3) indicate the direction of the electric field in the region just below the thin sheet with a second row

4) what is the electric field inside the top thick plate

3

Explanation / Answer

As given in the question,

Surface charge density: Q/A = + 2.5*10^-3 C/m^2

(a) Using Gauss's law,

Electric flux: = Q / 0 = E*A

     => E = (Q/A)*(1/0)   , where 0 = 8.85*10^-12 F/m

= (2.5*10^-3)*(1 / 8.85*10^-12) = 2.82*10^8 N/C

(b) For the direction of the electric field in the region just above the thin sheet,

Since the charge on the sheet is positive charge,

So, the electric field on it's upper side will towards UPWARD   ("")

(c) For the direction of the electric field in the region just below the thin sheet,

Since the charge on the sheet is positive charge,

So, the electric field on it's lower side will towards DOWNWARD   ("")

(d) For the final charge on any thick plate, we need it's surface area which is not given in the question.

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