two friends each contain about 4 x 10^28 electrons and an equal number of proton

Question

two friends each contain about 4 x 10^28 electrons and an equal number of protons.
Part A- Determine the force of their interaction if 2.0% of one friend's electrons are transferred to other, who is about 120 m away? Express your answer to two significant figures and include the appropriate units.

Part B- Determine the mass of the electrons transferred. Express your answer to two significant figures and include the appropriate units. two friends each contain about 4 x 10^28 electrons and an equal number of protons.
Part A- Determine the force of their interaction if 2.0% of one friend's electrons are transferred to other, who is about 120 m away? Express your answer to two significant figures and include the appropriate units.

Part B- Determine the mass of the electrons transferred. Express your answer to two significant figures and include the appropriate units. two friends each contain about 4 x 10^28 electrons and an equal number of protons.
Part A- Determine the force of their interaction if 2.0% of one friend's electrons are transferred to other, who is about 120 m away? Express your answer to two significant figures and include the appropriate units.

Part B- Determine the mass of the electrons transferred. Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

No of electrons = 4 x 10^28
Electrons Transferred = 0.02 *  4 x 10^28 = 8 *10^26
This electrons will cancel exactly same number of protons.

Eletrons left = 0.98 * 4 x 10^28 = 3.92 * 10^28
Charge of Electrons = 3.92 * 10^28 * 1.6 * 10^-19 C = 6.272 * 10^9 C

a)
Force = K q1 q2 / r^2
k = 8.9 * 10^9 Nm^2/c^2
r =120 m
q1 = q2 = 6.272 * 10^9 C

F = (8.9 * 10^9 * ( 6.272 * 10^9 )^2) /120^2
F = 2.43 * 10^25 N
Force of their interaction F = 2.43 * 10^25 N

b)
Mass of 1 electron = 9.1 * 10^-31 Kg
Mass of transferred electrons = 9.1 * 10^-31 Kg * No of Electrons transferred
Mass of transferred electrons = 9.1 * 10^-31 * 8 *10^26 * 1000 g
Mass of transferred electrons = 0.728 g

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