Laboratory Report Name: Partner\'s Name: Molarity of Stock KMnO, solution: Molar

Question

Laboratory Report Name: Partner's Name: Molarity of Stock KMnO, solution: Molarity of diluted KNno, solution: a 00 Date Instructor's Initials: Part 1 Trial 1 Trial 2 Trial 3 Initial Buret Reading of KMnO4 Final Buret Reading of KMnO 35 1357.15 Volume of KMnO4 used for Titration mmoles of MnO4 mmoles of C,0. 3 [Ba2+] Ksp Shqw your calculations for Trial 1I below. - + 000 om3 from the solubility you found in um o ations for the Ksp O The CRC Handbook of Chemistry and Physis L C00410413nd 50 CM3 PAET OF Tei AL 1 CALCUATOS

Explanation / Answer

Solubility of BaC2O4 and Ksp calculation

From the handbook of chemistry and physics

Solubility of BaC2O4 = 0.0075 g in 100 g water

moles of BaC2O4 = grams/molar mass

                              = 0.0075 g/225.34 g/mol

                              = 0.0000332 mol

density of water = 1 g/ml

So,

volume of water = 100 g/1 g/ml

                          = 100 ml

                          = 0.1 L

molar concentration of BaC2O4 = 0.0000332 mol/0.1 L

                                                    = 0.000332 mol/L

Ksp of BaC2O4 = [Ba2+][C2O4^2-]

[Ba2+] = [CaO4^2-] = 0.000332 mol/L

So,

Ksp = (0.000332)(0.000332)

       = 1.10 x 10^-7

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