The copper(II) chloride and aluminum reaction. calculate the kilojoules of heat
ID: 580754 • Letter: T
Question
The copper(II) chloride and aluminum reaction. calculate the kilojoules of heat produced by the reaction, assuming that no energy left the calorimeter.
The specific heat of the solution is 3.96J/gC ( include the mass of the aluminum foil in the total mass of the solution.
Data: Trial 1 Trial2
mass of calorimeter: 8.473g 8.610g
mass of solid Cucl2*2H2O: 3.232g 3.236g
mass of copper solution: 64.594g 62.637g
mass of aluminum foil: 0.814g 0.807g
initial temperature: 19.6C 20.8C
final temperature: 49.2C 53.4C
Explanation / Answer
The specific heat of the solution is 3.96J/goC ( include the mass of the aluminum foil in the total mass of the solution.
Data: Trial 1
mass of calorimeter: 8.473g
mass of solid Cucl2*2H2O: 3.232g
mass of copper solution: 64.594g
mass of aluminum foil: 0.814g
initial temperature: 19.6oC
final temperature: 49.2oC
T (Change in Temperature) = 49.2 -19.6 = 29.6oC
q for trial 1 = m * C * T
C = specific heat of the solution is 3.96J/goC
m = mass of the reactant = (mass of copper solution - mass of calorimeter - mass of solid Cucl2*2H2O - mass of aluminum foil) = (64.594 - 8.473 - 3.232 - 0.814 )g = 52.075 g
therefore,q for trial 1 = m * C * T = 52.075g * 3.96J/goC *29.6oC = 6104.02 J
1KJ = 1000J
q for trial 1 = 6.104 KJ
Data: Trial 2
mass of calorimeter: 8.610g
mass of solid Cucl2*2H2O: 3.236g
mass of copper solution: 62.637g
mass of aluminum foil: 0.807g
initial temperature: 20.8oC
final temperature: 53.4oC
T (Change in Temperature) = 53.4 -20.8 = 32.6oC
q for trial 2 = m * C * T
C = specific heat of the solution is 3.96J/goC
m = mass of the reactant = (mass of copper solution - mass of calorimeter - mass of solid Cucl2*2H2O - mass of aluminum foil) = (62.637 - 8.610- 3.236 - 0.807 )g = 49.984 g
therefore,q for trial 2 = m * C * T = 49.984g * 3.96J/goC *32.6oC = 6452.73 J
1KJ = 1000J
q for trial 2 = 6.452 KJ
Therefore,the kilojoules of heat produced by the reaction, assuming that no energy left the calorimeter for trial 1 & trial 2 = 6.104 KJ + 6.452 KJ = 12.5567 KJ
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