4 to n-s transition n thery rogan atom ( % ) 4 7. Calculate the wavelength and e

Question

4 to n-s transition n thery rogan atom ( % ) 4 7. Calculate the wavelength and energy corresponding to the n- 8. Calculate the percentage ionic character of the HCl, HI, and CO bonds from the following data: (6%) CO 127 160 113 Internuclear distance/pm Dipole moment/1030 Cm 3.60 1.40 0.33 9. Consider the following molecules H2, CO2, 2o, CHCI, H202, NH3. Which of them will give a) a pure rotational spectrum, b) a vibrational-rotational spectrum, c) a pure rotational Raman spectrum, d) a vibrational Raman spectrum? (6%) would the average speed of (a) an H2 molecule and (b) an O2 molecule be equal to this escape speed? (6%) Compare that value with the efficiency of packing circles onto a triangular lattice. (c) Which packing uses area 10. The speed that a body of any mass must have to escape from the earth is 1.07 x 101 ms1. At what temperature 11. (a) Determine the eficiency of area utilization in packing circles onto the lattice points of a square lattice. (b) more efficiently and by how much? (696) 12·The compo sition of a protein corresponds to 5 mol of molar mass 30,000 g mol and 10 mol of molar mass 60,000 g mol-1. Calculate the number-average and mass-average molar masses. (6%) (Physical constants: Avogadro constant 6.022 x 1023 mor1; Planck constant 6,626 x 104J s; Rydberg constant 1.097 x 10'm; Boltzmann constan 1.381 x 103 j K1; Speed of light in vacuum 2.998 x 10* ms1; Elementary charge 1.602 x 101" c) (Atomic weight: Ca 40.08; F 19.00; H 1.008; O 16.00)

Explanation / Answer

Q7.

Apply Rydberg Formula

E = R*(1/nf^2 – 1/ni ^2)

R = -2.178*10^-18 J

Nf = final stage/level

Ni = initial stage/level

E = Energy per unit (i.e. J/photon)

E = (-2.178*10^-18)*(1/5^2 – 1/4 ^2)

E = 4.90*10^-20 J/photon

For the wavelength:

WL = h c / E

h = Planck Constant = 6.626*10^-34 J s

c = speed of particle (i.e. light) = 3*10^8 m/s

E = energy per particle J/photon

WL = wavelength in meters

WL = (6.626*10^-34)(3*10^8)/(4.90*10^-20)

WL = 4.056*10^-6 m

to nanometers:

WL = (4.056*10^-6 )(10^9) = 4056 nm

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