A 9.24 g sample of 1,4-pentadiene (formula CsHg), is mixed with 247.37 atm of O2

Question

A 9.24 g sample of 1,4-pentadiene (formula CsHg), is mixed with 247.37 atm of O2 in a 1.93x10-1 L combustion chamber at 318.71 °C. The combustion reaction to Co2 and H20 is initiated and the vessel is cooled back to 318.71 °C, Report all answers to two decimal places in standard notation (ie. 1.23 atm) 1. What is Pco2 (in atm) in the combustion chamber assuming the reaction goes to completion? Assume all water is water vapour and that the volume of the system does not change 118.4981m1oc Submit AnswerIncorrect. Tries 1/3 Previous Tries

Explanation / Answer

C5H8 + 7O2 ---> 5CO2 + 4H2O

1 mol C5H8 = 7 mol O2

no of mol of C5H8 = 9.24/68 = 0.136 mol

nO OF mol of O2 = PV/RT

                = (247.37*0.193)/(0.0821*(318.71+273.15))

                = 0.98 mol

limiting reactant = C5H8

no of mol of CO2 produced = 0.136*5 = 0.68 mol

pressure of CO2(pCO2) = nRT/V

                       = 0.68*0.0821*(318.71+273.15)/0.193

                       = 171.2 atm

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