15 MOLAR MASS FROM FREEZING POINT DEPRESSION DATA 1. Calibration of the thermome

Question

15 MOLAR MASS FROM FREEZING POINT DEPRESSION DATA 1. Calibration of the thermometer 2. Mass of the test tube 3. Freezing point of t-butyl alcohol 4. Mass of test tube and t-butyl alcohol 5. Mass of t-butyl alcohol 6. Unknown used 7. Mass of test tube, t-butyl alcohol, and unknown 8. Mass of the unknown 9. Freezing point of the mixture 10. Freezing point depression, AT to 8 g. 1.10 2.501 11. Calculate the molality of your solution 111.- alorin Molality =0.4225m 12. Calculate the moles of unknown Moles . 13. Calculate the molar mass of your unknown Molar Mass =

Explanation / Answer

12.

Mass of solvent = 7.19 g. = 0.00719 kg.

Molality = moles of solute / mass of solvent in kg

0.4725 = moles of solute / 0.00719

Moles of solute = 0.00340 mol

13.

Mass of unkonwn = 0.501 g.

Moles = mass / molar mass

0.00340 = 0.501 / molar mass

Molar mass of unknown = 0.501 / 0.00340 = 147.5 g/mol

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