a 25.00 mL volume of a standardized .0235 mHCL solution tirades 25.0 mL of a sat

Question

a 25.00 mL volume of a standardized .0235 mHCL solution tirades 25.0 mL of a saturated Ca(OH)2 solution to the methylene orange endpoint. Calculate the Ksp of Ca(OH)2 a 25.00 mL volume of a standardized .0235 mHCL solution tirades 25.0 mL of a saturated Ca(OH)2 solution to the methylene orange endpoint. Calculate the Ksp of Ca(OH)2 a 25.00 mL volume of a standardized .0235 mHCL solution tirades 25.0 mL of a saturated Ca(OH)2 solution to the methylene orange endpoint. Calculate the Ksp of Ca(OH)2

Explanation / Answer

mmol of acid = MV= 25*0.0235 = 0.5875

mmol of base = 1/2 mmol of acid = 0.5875/2 = 0.29375

then

[Ca(OH)2] = mmol/V = 0.29375 / 25 = 0.01175 M

[OH-] = 2*0.01175 = 0.0235

Ksp = [Ca+2][OH-]^2

Ksp = (0.01175 )(0.0235^2) = 6.488*10^-6

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