ding Limiting Reactant and Theoretical Yield 3 0f5 Part A be mple. After stions

Question

ding Limiting Reactant and Theoretical Yield 3 0f5 Part A be mple. After stions at the Ammonia can also be synthesized by this reaction 3H2(g) + N2 (g)- 2NH3 (g) What maximum amount of ammonia in grams can be synthesized from 25 2 g of N2 and 842 g of H2? Express your answer in grams to one decimal place. 78.96 g NH Submit as A Incorrect: Try Again: 7 attempts remaining This is the quantity of grams H2 given in masses The compound that produces the smaliest amount of product is the limiting reactant the question To det e the maximum amount of that can be syn y the reaction Be certain you have performed two separate calculations one to determine t of determine

Explanation / Answer

3H2 + N2 ----------> 2NH3

according to balanced reaction

28 g N2 reacts with 3 x 2 g H2

25.2 g N2 reacts with 25.2 x 3x 2 / 28 = 5.4 g H2

but we have 8.42 g H2. so H2 is exess reagent

N2 is limting reagent

Limiting reagent = N2

28 g N2 fomrs 2 x 17 g NH3

25.2 g N2 forms 25.2 x 2 x 17 / 28 = 30.6 g NH3

mass of NH3 formed = 30.6 g

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