Please respond with step by step solution please. Thank you. Part A The rate con

Question

Please respond with step by step solution please. Thank you.

Part A The rate constant for a certain reaction is k 7.20 10s. if the initial reactant concentration was 0.500 M, what will the concentration be after 19.0 minutes? Express your answer with the appropriate units. View Available Hint(s) Value Units Submit Part B A zero-order reaction has a constant rate of 360-10-4 M/s If after 40.0 seconds the concentration has dropped to 7.00-10-2 M, what was the initial concentration? Express your answer with the appropriate units. View Available Hint(s Value Units Submit

Explanation / Answer

A)
we have:
[A]o = 0.500 M
t = 19.0 min = 19.0*60 s = 1140 s
k = 7.2*10^-3 s-1
Given:
[A]o = 0.5 M

use integrated rate law for 1st order reaction
ln[A] = ln[A]o - k*t
ln[A] = ln(0.5) - 7.2*10^-3*1140
ln[A] = -0.6931 - 7.2*10^-3*1140
ln[A] = -8.9011
[A] = 1.36*10^-4 M
Answer: 1.36*10^-4 M

B)
we have:
[A] = 0.07 M
t = 40.0 s
k = 3.6*10^-4 M/s

use integrated rate law for 0 order reaction
[A] = [A]o - k*t
0.07 = [A]o - 3.6*10^-4*40
[A]o = 0.0844 M
Answer: 0.0844 M

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