iPad 8:21 PM * 67% Old Unit 1 Test #1: Attempt 1 Question Completion Status: UES

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iPad 8:21 PM * 67% Old Unit 1 Test #1: Attempt 1 Question Completion Status: UESTION 18 The solubility of neon gas, Ne(g), in water at 25.0 °C is 1.05 x 10-3 M when the pressure of the Ne above the solution is 1 .00 atm. The solubility of Ne(g) at a pressure of 3.55 atm is M. Express your answer in scientific notation (format #E8) 5.00000 points Save Answer UESTION 19 A solution is prepared by dissolving 13.7 g of NH3 in 250.0 g of water. The density of the resulting solution is 0.974 g/mL. The molarity of NH3 in the solution is 5.00000 points Save Answer

Explanation / Answer

18)
Henry’s law is:
P = KH*C
P is pressure above the solution
KH is Henry law constant
C is solubility

So,
P2/P1 = C2/C1
3.55 / 1.00 = C2 / (1.05*10^-3 M)
C2 = 3.73*10^-3 M

Answer: 3.73E-3 M

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