4. (40 pts.) This Question includes [e1, e2, e3] A natural gas has the following

Question

4. (40 pts.) This Question includes [e1, e2, e3] A natural gas has the following molar analysis: co2 0.5%, CH4 92% C2HA 3% N2 4.5%. The gas is burned with dry air, using Orsat analysis with the following results: co, 9.39% ; co 0.85% 02 2.88% [el, 10 points Identify the type of combustion analysis used in this problem Formulate the stoichiometric reaction for complete combustion and show all your work a) b) [e2, 10 points [e3, 20 points] c) Solve -The theoretical air-fuel ratio on a molar basis using stoichiometric approach. -The percent excess air and the actual air fuel ratio based on Kg of air over Kg of fuel gas

Explanation / Answer

a)

since this does not contains water, then this is "dry" analysis

b)

C2H4 + O2 = CO2 + H2O

balnace

C2H4 + 3O2 = 2CO2 + 2H2O

now..

CH4 + O2 = CO2+ H2O

balnace

CH4 + 2O2 = CO2+ 2H2O

c)

theoretical air - fuel ratio :

assume a basis of 100 mol

then

92 mol of methane --> 2*92 = 184 mol of O2

3 mol of C2H4 = 3*3 = 9 mo lof O"

total O2

184+9 = 193 mol of O2 required

air -> 1/0.21*193 = 871.428 mol of air

air:fuel ---> 871.428 mol of air per 100 mol of "fuel"

ratio 100% combustion = 8.71

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