4. (28 points) In a study on the treatment of bilateral ear infections in otherw

Question

4. (28 points) In a study on the treatment of bilateral ear infections in otherwise healthy adults, some doctors encourage a "wait and see approach" wh antibiotics. Those doctors advocating for the "wait and see approach" claim that infections tend to clear up on their own within 1-2 weeks without treatment and do not want to contribute to the problem of overuse of antibiotics which can create resistance. Other doctors; however, are more concerned about the negative side effects of an untreated infection and will prescribe an antibiotic right away for an infection. In a study, researchers wanted to compare t see" approach to the antibiotic approach in 90 adults with a bilateral ear infection. In this study doctors prescribed an antibiotic drop for one of the ears and a "wait and see" approach for the other ear. After 2 weeks, each ear was assessed to see if the infection was cured. The results are presented below. Test at the 0.05 level whether there is an association between treatment ("wait and see" vs antibiotic drop) and cure of the ear infection. ereas others treat right away with he "wait and Wait and See Yes No Yes 519 Infection Cured in Antibiotic Ear Drop No 2 18 a. Which test seems most appropriate? Be as specific as possible. b. Label and describe the parameters involved. c. State the hypotheses.

Explanation / Answer

Answer to the question)

Part a)

Chi square test of independence is the most appropriate test for this data

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Part b)

There are two facotrs: Treatment given & cured or not

In this case: treatment given is independent factor with two levels

Curing is the dependent factor with two levels: yes or no

The parameters would be observed counts and expected counts

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Part c)

The hypothesis is as follows:

Null hypohtesis: The treatment and curing has no association

Alternate hypohtesis: The treatment and curing are associated

.

Part d)

The significance level is provided in the question itself

Alpha = 0.05

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