Introductory Biochemistry, BCH 3053 – Spring 2017 EXAM #1: February 17, 2017 Nam

Question

Introductory Biochemistry, BCH 3053 – Spring 2017 EXAM #1: February 17, 2017 Name: 4. You discover an unusual species of bacteria, Bacillus studyatusfillus. This bacterium contains an unusual amino acid, based on glutamic acid. For this unusual amino acid, a hydrogen atom on the carbon-3 (the y-carbon) is replaced with another amino group. What is the isoelectric point (p) for this unusual amino acid given the list of pK, values below? pKa-COOH = 2.1 pKR-COOH = 4.3 pKa-NH3 = 9.3 pKr-NH3 = 10.7 pl = 3.2 pl = 4.3 C. pl = 6.8 D. pl = 7.5 E. pl = 9.3

Explanation / Answer

Biochemistry

4. for the unsual species of bacteria found

we have -NH3 group replaced in place of -H atom in the amino acid

the isoelectric point of the given amino acid would thus be,

pI = (10.7 + 4.3)/2

    = 7.5

Answer,

D. pI = 7.5

at this pH 7.5, the net charge on the structure would be zero.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.