The hybridization of the central carbon in CHi3CeN and the bond angle CCN are a)
ID: 576104 • Letter: T
Question
The hybridization of the central carbon in CHi3CeN and the bond angle CCN are a) sp, 180° 12. b) sp? and 120 c) sp3 and 109.5 d)Jsp and 180 13. What are the hybridizations of atoms 1 and 2 respectively in the followin 2 8 a)) sp3 and sp sp and sp? sp and sp c) sp3 and sp d) sp2 and sp 14. What are the hybridizations of carbons 1 and 2 respectively in the following structure? a) sp and sp" sp2 and sp3 c) sp3 and sp d) sp2 and sp e molecular geometry for the central carbon in acetone, (CHa) CO, is best described as 15. a) Linear b) Bent Tetrahedral d) Trigonal planar 16. In the following equilibrium where HX is a stronger acid than HY, predict the position of the equililbrium. Cca a) The equlibrium favors the weakest acid and the strongest base b) The equilibrium favors the weakest acid and the weakest base c) The equilthrium favors the strongest acid and the strongest base d) The equilibrium favors the strongest acid and the weakest base 17. In the following reaction where HX is a stronger açid than HY, which of the following is true for l 7. In the follo equilibrium constant Kes? HY + Nax Nay + H a) Kea> 1 c) Keq=0 d) Keq=10Explanation / Answer
12)
central C forms 1 triple bond with N and 1 single bond with C
So, total number of electron domain = 2
So, it is sp hybridised
Angle for sp is 180 degree
Answer: d
13)
N forms 2 sigma bond and has 1 lone pair
So, it is sp2
C forms 3 sigma bonds (2 with carbon and 1 with hydrogen that is shown)
So, it is sp2
Answer: d
14)
1 forms 2 sigma bonds will 2 carbon and 2 with hydrogen
So, total number of electron domain = 4
So, it is sp3 hybridised
2 forms 2 sigma bonds will 2 carbon and 1 with hydrogen
So, total number of electron domain = 3
So, it is sp2 hybridised
Answer: a
15)
central C forms double bond with O and 2 single bond with CH3
So, total number of electron domain = 3
So, it is sp2 hybridised
Hence it is trigonal planar
Answer: d
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