The hybridization of nitrogen in the H-C=N: molecule is sp s^2p s^3p sp^2 sp^3 T
ID: 1059340 • Letter: T
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The hybridization of nitrogen in the H-C=N: molecule is sp s^2p s^3p sp^2 sp^3 The molecular geometry of the PHCl_2 molecule is bent trigonal planar trigonal pyramidal tetrahedral T-shaped The F-N-F bond angle in the NF_3 molecule is slightly less than 90 degree 109.5 degree 120 degree 180 degree 60 degree The hybridization of orbitals on the central atom in the molecule is sp^2. The electron-domain geometry about this central atom is octahedral linear trigonal planar trigonal bipyramidal tetrahedralExplanation / Answer
The Lewis structure of HCN
H:C:::N:
To determine the orbital hydridization, the Single, double, and triple bonds present in the structure accounts to be a group each one.even the lone pairs of electrons accounts as group.
Thus, the no of electron groups gives orbital hybridization.
if two electron groups, then the central atom will have sp hybridization.
If three electronscgroups, then central atom is sp2 hybridized.
if electrons four groups, then the central atom is sp3 hybridized.
Depending upon these, a triple bond exists between carbon and nitrogen.
A triple bond has an end-to-end overlap of two sigma bonds and one side-to-side overlap of two unhybridized p-orbitals.
Therefore, in this case nitrogen has sp hybridization.
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