chae10 ± Deriving Gas Law Formulas previous| 5of 13 Inext . P 2 atm2atm 17L 25L

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chae10 ± Deriving Gas Law Formulas previous| 5of 13 Inext . P 2 atm2atm 17L 25L n 0.45 mol 0.45 mo T 273 K It is clear that V and T are the quantities that are changing, while P and n are constant. To put all constants P, n, and R together, we need to do a little bit of algebra 1, PV = nRT. 4. is constant. 5. Therefore the quantity V/T at any point in time will be the same value as at any other point in time, so This last equation is the best formula to use when only volume and temperature are changing Now to solve for the missing value, simply substitute numbers into this formula 273 K which gives T2 = 401.5 K Derive a gas law formula for a specific scenario One mole of an ideal gas is sealed in a 22.4-L container at a pressure of 1 atm and a temperature of 273 K. The temperature is then increased to 311 K, but the container does not expand. What will the new pressure be? Part A The most appropriate formula for solving this problem includes only which variables? Enter the required variables, separated by commas (e.g., .) Hints Submit My Answers Give Up

Explanation / Answer

Here Volume is not changing

we are bothered about Pressure and Temperature

So, answer should be P and T

Answer: P,T

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