Solution Making Exercise (due next lab session, typed as per course guidelines)

Question

Solution Making Exercise (due next lab session, typed as per course guidelines) 1. Describe how to make 250 mls of a solution that contains l mM nssmM 50 mM NaCI from stocks of 1 M Tris, 0.5 M EDTA, 5 MNaCl olo M ZI mol 4 Describe how to make 500 mls of20% BSA (w/v), (FW-160) 0 …rn-) 5. Describe how to make 100 mls of 20% Methanol (v,v), 50 mM Tris. 6. Describe how to make one liter of the following solution: 0.3 M mannitol (FW- 182), 0.02 M KP04, 0.01 M KCI, 0.005 M MgCI2. You have the following stocks.. I M KP04, IM KCI, I M MgC12 7. Describe how to make 1.25 liter of 4 M NaCI (FW- 40) 8. Describe how to make 250 mls of 250 mM Tris, pH 8.9 Tooe 160n 10. Describe how to make 200 mls of 10 mM EDTA (FW-180), pH 8.0

Explanation / Answer

4.

20% w/v means that mass of BSA will be 20% of the total volume. In this case, mass of BSA = 20% of 500 = 100 g

Dissolve 100 g BSA in 500 mL DW to make the solution.

5)

Moles of Tris needed = Molarity * Volume = 0.05*0.1 = 0.005 moles

Mass of Tris needed = moles*FW = 0.005*121 = 0.605 g

Volume of methanol = 20% of 100 mL = 20 mL

Add 0.605 g Tris, 20 mL methanol and 80 mL DW to make the solution.

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