Solubility of Benzoic Acid in Water 60 50 40 1479e0337% 0.9955 20 10 20 40 60 80

Question

Solubility of Benzoic Acid in Water 60 50 40 1479e0337% 0.9955 20 10 20 40 60 80 100 A graph of temperature (°C) versus solubility of benzoic acid in water (g/L) has a good exponential fit, y = 1.479e indicated by the Goodness of Fit R 0.9955. Given that you used 10.9 ml of water to dissolve 0.430 g of benzoic acid, what was the actual temperature of your recrystallization setup according to this exponential equation? Don't forget that there are 1000 ml in a liter. Round to a whole number answer without any decimal point. Answer.

Explanation / Answer

Mass of benzoic acid = 0.430 g

Volume of water = 10.9 ml = 0.0109 L

solubility = 0.430/0.0109 = 39.45 g/L

The equation ograph is:

y = 1.479e0.0357x

y = solubility = 39.45 g/L

Put this value in equation, the find x.

39.45 = 1.479e0.0357x

take log on both sides

log 39.45 = log 1.479 + 0.0357x log e

1.596 = 0.170 + 0.0357x(0.434)

1.426 = 0.0155x

x = 92

Temperature = x = 92 oC

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