You are working with two varieties of apples. one variety has the genotype AB/AB

Question

You are working with two varieties of apples. one variety has the genotype AB/AB. The "A" allele in the variety causes the fruit to be non-browning but the "B" allele causes the fruit to be soft. Your other variety of apple has the genotype ab/ab. This variety of apple browns eaily but has crisp fruit. You really would like to develop a true-breeding variety of apple that has crisp non browning fruit. Unfortunately, the A and B are closely linked- 5 cM apart. You cross AB/AB x ab/ab to obtain f1 progeny, and then cross these f1s to each other to obtain f2. If you analyze 10,000 f2 progeny, how many would you predict to have the genotype that you desire?

Explanation / Answer

AB/AB x ab/ab

AbaB is recombinant genotype.

A and B are linked and 5cM apart means, recombinants are 5%.

then, 95% offsprings are parental type.

Of total 10,000 F2 progeny, the recombinants produced with desired characteristics include = 10000 x 5 / 100 = 500.

About 500 F2 progeny can be predicted to have desired genotype.

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