A. Reaction Pathway A. Reaction Pathway 5) The process of dissolving Hydrazine (

Question

A. Reaction Pathway A. Reaction Pathway 5) The process of dissolving Hydrazine (N2Ha) involves a AH a. Write the thermochemical equation with energy terms. Endo can absorb or release energy b. of 109 3 kJmol. (4 marks) Write a thermochemical equation with H values. c. Write the molar enthalpy equation for this process. Reaction Draw a complete potential energy diagram for this reaction 6) 75 mL of 0.400 mol/L sodium hydroxide was neutralized with 55 mL of sulphuric acid solution. The temperature increased by 12.4'C. Calculate the molar enthalpy of neutralization of sodium hydroxide. (8 marks) -> 4A1 + 30 lorimetry Gas Liquid-KE PE Solid-KE fnllowinn reaction: (6 marks)

Explanation / Answer

Ans 6

The balanced chemical equation

H2SO4(aq) + 2 NaOH(aq) = Na2SO4(aq) + 2 H2O(l)

Moles of NaOH = molarity x volume

= 0.400 mol/L x 0.075 L = 0.03 mol

Mass of NaOH = 0.03 mol x 40g/mol = 1.2 g

Molarity of H2SO4

= molarity of NaOH x volume of NaOH/volume of H2SO4

= 0.4 x 75/55

= 0.545 M

Moles of H2SO4 = 0.545 x 0.055 = 0.03 moles

Mass of H2SO4 = 0.03 moles x 98g/mol = 2.94 g

Total mass = 1.2 + 2.94 = 4.14 g

Heat produced =- (total mass × specific heat capacity × change in temperature)
= - (4.14 g x 4.184 J/g·C x 12.4C)

= - 214.78 J

Moles of H2O produced

= 0.03 mol NaOH x 2 mol H2O/2 mol NaOH

= 0.03 mol H2O

H neutral = heat produced / H2O produced

= - 214.78 J/0.03 mol

= - 7159.66 J/mol

= - 7.159 kJ/mol

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.