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Ethanol is a possible fue Use average bond energies to akoulate AH for the combu

ID: 570694 • Letter: E

Question

Ethanol is a possible fue Use average bond energies to akoulate AH for the combuation of tha Express your answer as an integer ANSWER Standard Enthalpy of Reaction Learning Goal: To understand how standard enthalpy of reaction is related to the standard heats of formation of the reactants and products The standard enthalpy of reaction is the enthalpy change that occurs in a reaction when al the reactants and products are in their standard state for the standard enthalpy of reaction is H s where tho sut script nn stands for react on The standard e a py of a esons can and standard heats of form ation H ) (subscript Trt at on) of its rea tants and p dicts. Therefore the Standard enthaw fm or any- mathematically determined, as long as the standard heats of formation (A Hf) of its reactants and products are known. In a generic chemical reaction involving reactants A and B and products C and D. aA +6BcC + dD, te strda d ertapy Hinofte given by Notice that the stoichiometric coefficients, a, b, c, d, are an important part of this equation. This formula is ofien generaized as follows, where the right-hand side of the equation is a sum over the products and the second sum is over the reactants where m and n represent the appropriate stoichiometric coefficients for each substance Part A What is Han for the following chemical reaction? H201) (1)-+COCIa (g) +2HCl(g) You can use the following table of standard heats of formation (AH?) to calculate the enthalpy of the given reaction Element Compound Standard Heat of Formation (llmol Standard Heat of Element Compound Formation (kJ/mol) 473 N(g) 02(8 0(g) HCl(g) COCl (g) H(g) Ha(8) 218 H20(0) C(g) C(s) -139.5 -285.8 71 0 249 -92.30k -218.8k -206.6 HNOa (aq)

Explanation / Answer

Part A)

For the given chemical reaction,

H2O(l) + CCl4(l) ---> COCl2(g) + 2HCl(g)

dHo(rxn) = dHo(products) - dHo(reactants)

taking values from the table,

dHo(rxn) = (-218.8 + 2 x -92.30) - (-285.8 - 139.5)

               = 21.9 kJ/mol

So, dHo(rxn) for the above shown chemical reaction is 21.9 kJ/mol

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