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Pad 1:21 PM 82% Cytochrome a3 (Fe3+ ) + e- cytochrome a3(Fe2+ ) 0.385 0.295 0.29

ID: 570047 • Letter: P

Question

Pad 1:21 PM 82% Cytochrome a3 (Fe3+ ) + e- cytochrome a3(Fe2+ ) 0.385 0.295 0.29 0.235 0.22 0.077 0.045 0.031 + 2H+ + 2e- H2O- Cytochrome a(Fe3+ ) + e- cytochrome a(Fe2+ ) Cytochrome c(Fe3+ ) + e- cytochrome c(Fe2+ ) Cytochrome C1 (Fe'*) + e- cytochrome cl (Fe*) Cytochrome b(Fe3+1+ e- Cytochrome a(Fe2+ )(mitochondrial) Ubiquinone 2H+ 2eubiquinol Fumarate-+ 2H+ + 2e- succinate- FAD + 2H+ + 2e- FADH2 (inflavoproteins) Oxaloacetate-+ 2H+ + 2e- malate Pyruvate 2H 2e lactate Acetaldehyde 2H 2e ethanol FAD 2H 2eFADH2 (free coenzyme) S + 2H+ + 2e- H2 S Lipoic acid 2H+ 2edihydrolipoic acid NAD+ + H+ + 2e- NADH NADP+ + H+ + 2e- NADPH Cysteine disulfide +2H+ 2e2 cysteine Acetoacetate-+ 2H+ + 2e- -hydroxybutyrate- 0.040 0.166 0.185 0.197 -0.219 0.23 - 0.29 CLOSE 0.315 0.320 0.340 0.346 0.421 0.515 0.581 2 sof + 2H+ +2e- SOF + H2O Acetate +3H+ 2e acetaldehyde H2O

Explanation / Answer

Prokaryotes

14A)

From the table,

the electron acceptor is -0.023 V

the electron donor is -0.581 V

Using the values,

Eo = Ecathode - Eanode = -0.023 - (-0.581) = 0.558 V

Free energy dGo

dGo = -nFEo

with,

F = Faraday's constant

n = 2

we get,

dGo = -2 x 96500 x 0.558/1000 = -107.694 kJ