2. What is the molarity of 0.500 L of NaOH solution if it contains 6.00 g of NaO

Question

2. What is the molarity of 0.500 L of NaOH solution if it contains 6.00 g of NaOH? a. Determine the quantities of solute and solution. b. Write the concentration expression c. Substitute solute and solution quantities into the expression. 3. Calculate the molarity of a solution formed by taking 350 mL of 2.25 M HCI and adding 420 mL of water. Assume volumes are additive. Prepare a table of the concentrations and volumes of the solutions. My= M2 = a. b. Rearrange the dilution expression to solve for the unknown quantity. c. Substitute the known quantities into the dilution expression and solve.

Explanation / Answer

Ans2:

mass of NaOH = 6.00g

moles of NaOH = 6.00/MW = 6/40 = 0.15 moles NaOH

volume of NaOH = 0.500lt

a) quantity of solute = 0.15 moles NaOH

b) quantity of solution = 0.500Lt

c) Molarity = moles of solute/quantity of solution = 0.15/0.005 = 0.3M

Ans3:

a) For HCl: M1 = 2.25M, V1 = 350ml

For dilute solution M2 = ?, Volume of water added V2 = 420ml water

b) M1V1 = M2(V1+V2) => 2.25*350 = M2(350+420)

c) M2 = 1.023M

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