The pattern of transcription for a pair of identical twins (Tweedledee and Tweed

Question

The pattern of transcription for a pair of identical twins (Tweedledee and Tweedledum) is very similar at the age of 10. However by the time they are 50, transcription of the leptin gene is much higher in Tweedledee than in Tweedledum. This could be due to what change in Tweedledee?

A. Spontaneous mutation in their father’s sperm cell

B. Histone acetylation at the site of Tweedledee leptin gene

C. DNA methylation at the site of Tweedledee's leptin gene

D. DNA phosphorylation at the site of Tweedledum’s leptin gene

E. A crossing over event during meiosis in their mother’s egg cell

Explanation / Answer

The correct answer would be :B. Histone acetylation at the site of Tweedledee leptin gene.

Reason:Twins are identical genetically.Changes in the gentic make up at later age occurs due to epigenetic modifications and these modifications include histone acetylation and DNA phosphorylation that increase the transcription level.Since in this case, transcription of the leptin gene is much higher in Tweedledee than in Tweedledum, so option B.would be correct.

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