32. (I0pts) The enzyme aldolase catalyzes the following reaction in the glycolyt

Question

32. (I0pts) The enzyme aldolase catalyzes the following reaction in the glycolytic pathway: Fructose 1,6- The standard free energy for the rea A. Calculate the ratio of the reactants to products under equilibrium conditions. bisphosphate dihydroxyacetone phosphate + glyceraldehyde 3-phosphate ction is +23.8 kJ/mol, whereas AG in the cell is -1.3 kJ/mol. mo t mot K B. Calculate the ratio of reactants to products under cellular conditions. 23,8% + 2 40 x 10 -1,300 : 8.314ne&K; (298 K) mot me l mot.k R. 2.5 tari inverne ? C. Using your results, explain how the reaction can be endergonic under standard conditions but exergonic under cellular conditions. C-unden standard conditon, the mn ea to the ttt, neaching eguilibriun when ony a amall amount lulatin o eactantle fumed ontaneou

Explanation / Answer

A)

ratio of R/P implies:

dG = dG° + RT*ln(Q)

in equilbirium, DG = 0

0= dG° + RT*ln(Q)

23.8*10^3 = -8.314*298*ln(Q)

Q = exp((23.8*10^3 )/( -8.314*298)) = 0.0000673

this is products/reactants = 0.0000673

we need the reversed -->  

R/P = 1/0.0000673= 14858.84

c)

note that we have

dG = dG° + RT*ln(Q)

if dG° --> standard conditions, is not favoured, this is positive

therefore, we need  RT*ln(Q) to be negative than dG°, this can only be achieved via ln(Q)

if Q <<< 1, then this is favoured towards reverse reaction

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