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C) indicator point D) volumetric point E) setpoint 13) is an oxidation reaction.

ID: 562040 • Letter: C

Question

C) indicator point D) volumetric point E) setpoint 13) is an oxidation reaction. 13)- A) Neutralization of HCI by NaOH B) Table salt dissolving in water for cooking vegetables ) Ice melting in a soft drink D) Rusting of iron E) The reaction of sodium chloride with lead nitrate to form lead chloride and sodium nitrate 14) 14) What is the concentration (M) of a NaCI solution prepared by dissolving 9.3 g of NaCl in sufficient C) 0.45 15) What are the respective concentrations (M) of Cut2 and Cl afforded by dissolving 0.871 mol CuC12 water to give 350 mL of solution? A) 18 B) 0.16 D) 27 E) 2.7 x 10-2 15) in water and diluting to 259 mL? A) 0.00336 and 3.36 B) 0.00336 and 0.00336 C) 3.36 and 3.36 D) 3.36 and 6.73 E) 0.297 and 0.113

Explanation / Answer

Answer:

13) (D) is correct.

Rusting of Iron is an oxidation reaction.

Fe Fe2+ + 2 e, The oxidation number of Fe increases, so it is oxidised.

14) (C) is correct.

Given mass f NaCl=9.3 g, volume=350 mL and we know that molar mass of NaCl=58.44 g/mol

Concentration (M)=(mass/molar mass)x1000/V(ml)=(9.3 g/58.44 g/mol)(1000/350)=0.4546 M

15) (D) is correct.

Given moles of CuCl2=0.871 mol and volume=259 mL=0.259L

concentration of CuCl2=mol/L=0.871 mol/0.259 L=3.36M.

In CuCl2, 1 mole of Cu+2 and two moles of Cl-.

So the concentration of Cu+2=conc.CuCl2=3.36 M and

the concentration of Cl-=2xconc.CuCl2=6.73 M.