Use the following atomic weights and quantities to calculate the theoretical yie

Question

Use the following atomic weights and quantities to calculate the theoretical yield of hydrogen gas, in liters, that should be given off by the reaction of phenylacetic acid, iron, and heat. Assume that at our elevation and laboratory temperature there are 22 liters per mole of an ideal gas. Balance the equation and remember that your yield must be based on the limiting reagent, and that grams must be converted to moles. Filling out most of the chart will help. Give only two significant digits in your answer. If after rounding the answer is a whole number, do not include a decimal point. C=12, H = 1, Fe = 56, 0-16 phenylacetic acid iron hydrogen gas formula formula weight grams moles 754.182 48.364 theoretical yield (liters)?

Explanation / Answer

molarmass of phenylaceticacid (C6H5-CH2-COOH) = 12*8+2*16+1*8 = 136 g/mol

   no of mol of phenylaceticacid = 754.182/136 = 5.545 mol

   no of mol of iron = 48.364/56 = 0.864 mol

from equation,

   6C6H5-CH2-COOH + 2Fe ----> 2Fe( 00C-CH2-COOC6H5)3 + 3H2(g)

6 mol phenylaceticacid = 2 mol iron = 3 mol H2

   limiting reactant = iron

no of mol of H2 liberated = 0.864*3/2 = 1.3 mol

volume of H2 liberated = 1.3*22 = 28.6 L

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