Use the following atomic weights and quantities to calculate the overall % yield

Question

Use the following atomic weights and quantities to calculate the overall % yield of benzil. Remember that your yield must be based on the limiting reagent, and that grams must be converted to moles. Filling out most of the chart will help. Give only two significant digits in your answer. If after rounding the answer is a whole number, do not include a decimal point. C-12, H # 1, Cus 63.5, N 14, O-16 benzoin +ammonium nitrate+ copper(ll) acetatebenzil formula formula weight 2.755 10.113 6.436 grams 43.314 moles 96 yield Answer:

Explanation / Answer

Benzoin + ammonium nitrate + copper (II) acetate -----------> Benzil

212.25         80.0                                181.6                                    210.23 g/mol     Fromula weight

43.314         2.755                           10.113                                       6.436                Grams

0.204           0.0344                          0.0557                                     0.0306         moles

From the balanced equation, ammonium nitrate is the limiting reagent.

Theoretical yield = 0.0344 mol of benzil = 0.0344 * 210.23 = 7.232 g.

Therefore,

% yield of benzil = 6.436 * 100 / 7.232 = 89.0 %

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