12. Standard temperature for gases is 25°C. 13. The SI unit of energy is the Jou
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12. Standard temperature for gases is 25°C. 13. The SI unit of energy is the Joule. 14. Gases move at very high speeds. __ 15 . Boyle determined that volume is inversely proportional to pressure. Short Answer and Problems (show your work if applicable) (10 pts) 16. Determine the enthalpy change for the production of acetylene from the following data. 2C(g) + H2(g) C2H2(g) AH-7 2C2H2(g) + 5 Odg) 4 CO2(g) +2 H2O(!) C(s) + O2(g) CO2(g) C(s) + O2(g) 2 CO(g) 2 H2(g) + O2(g) 2 H2O(l) AH=-2599.2 kl H =-393.5 kJ AH-221.0k H =-571.6 kJ (8 pts) 17. A mixture consisting of 0.100 mol N2, 0.050 mol 02, 0.200 mol CH, and an unknown amount of CO2 occupied a volume of 11.1 L at 27°C and 745 mmHg. How many moles of CO2 are there in the sample?Explanation / Answer
This is our target equation:
2C(s) + H2(g) ---> C2H2(g) H =?
Given Eqs:
(1) 2C2H2(g) + 5 O2(g) ---> 4CO2(g) + 2H2O(l) .....H = -2599.2 kJ
(2) C(s) + O2(g) ---> CO2(g) ......................H = -393.5 kJ
(3) 2C (s) + O2(g)---> 2CO (g).....................H = -221.0 kJ
(4)2H2(g) + O2(g) ---> 2H2O() .................. H = -571.6 kJ
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Reverse the equation(1);we get
(5) 4CO2(g) + 2H2O(l)-----> 2C2H2(g) + 5 O2(g).......H =+ 2599.2 kJ
Multiply the equation with 4; (2)x4 ==> we get;
(6) 4C(s) + 4O2(g) ---> 4CO2(g) ......................H = -1574.0 kJ
Now, add the equations (5) + (6) + (4) and cancel out all the species are common on both sides;
(5) 4CO2(g) + 2H2O(l)-----> 2C2H2(g) + 5 O2(g).......H = 2599.2 kJ
(6) 4C(s) + 4O2(g) ---> 4CO2(g) ......................H = -1574.0 kJ
(4)2H2(g) + O2(g) ---> 2H2O(l) .................. H = -571.6 kJ
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(7) 4C(s) + 2H2(g) ---> 2C2H2(g) H = 2599.2 kJ -1574.0 kJ -571.6 kJ
= 453.6 KJ
To get our required equation, devide equation(7) with 2; (7)/2;
we get;
2C(s) + H2(g) ---> C2H2(g) H =453.6 KJ/2 = 226.8 KJ
Hence, the answer is :
2C(s) + H2(g) ---> C2H2(g) H = 226.8 KJ
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