C-4 Sister Bumica the laboratory night manager has shortage of 162.0 g of Calciu

Question

C-4 Sister Bumica the laboratory night manager has shortage of 162.0 g of Calcium Chloride reagent (Ca Cla). She has provided you with a bottle of Calcium Carbonate powder dry (CaCOs) containing 150.0 g of Calcium Carbonate powder pure substance, and excess amounts of Concentrated Hydrochloric Acid (HCI). Using all chemicals in stock. S he urgently needs your help to prepare for lab, preferably 165.0 g of Calcium Chloride pure substance. You have prepared him only 148.0g. The following is the chemical reaction you need to follow up. (8points)

Explanation / Answer

Ans. Balanced Reaction:      CaCO3(s) + 2 HCl(g) ------> CaCl2(aq) + H2O(l) + CO2(g)

# Moles of CaCl2 required = Required Mass / Molar mass

                                                = 165.0 g / (110.9834 g/mol)

                                                = 1.4867 mol

# According to the stoichiometry of balanced reaction, 1 mol CaCO3 produces 1 mol CaCl2.

Therefore,

            Required moles of CaCO3= Required moles of CaCl2

Hence, Required moles of CaCO3 = 1.4867 mol

Now,

            Required mass of CaCO3 = Required moles x Molar mass

                                                = 1.4867 mol x (100.0872 g/ mol)

                                                = 148.80 g

Hence, required amount of CaCO3 to produce 165 g CaCl2 = 148.80 g

Note: The last line of question “you have prepared him ____” is NOT well defined. Please correlate the answer accordingly.

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