1. Convert 4 mmol of Magnesium powder (FW 24.31 g/mol), 4 mmol of bromobenzene (

Question

1. Convert 4 mmol of Magnesium powder (FW 24.31 g/mol), 4 mmol of bromobenzene (157.01 g/mol), and 4 mmol of acetophenone (FW 120.15 g/mol) into grams. 2. Show the synthetic transformation to be performed in the experiment in the space below What is the theoretical yield (in grams) of 1,1-diphenylethanol (FW 198.26 g/mol)? 3. Suggest a mechanism for the formation of 1,1-diphenylethanol from the Grignard reagent 4. Enter your results below from the experiment. a. Calculate your percent yield b. Melting pt c. TLC sketch

Explanation / Answer

Q1

a

4 mmol of Mg --> mass = mmol*10^-3 *MW = (4*10^-3)(24.31) = 0.09724 g of Mg

b

4 mmol of Bromobenzene --> mass = mmol*10^-3 *MW = (4*10^-3)(157.01) = 0.62804 g of Bromobenzene

c

4 mmol of Acetophenone--> mass = mmol*10^-3 *MW = (4*10^-3)(120.15) = 0.4806 g of Acetophenone

Q2

theoretial yield:

acetophenone + bromobenzene = 1,1,diphenylethanol

ratio i1 :1 so

4:4 = 4 mmol should be produced

mass = mmol*10^-3 * Mw = (4*10^-3)(198.26) = 0.79304 g of product

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.