3 My Courses Course Home Exercise 6.107 Syllabus Assignments Scores Course Tools

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3 My Courses Course Home Exercise 6.107 Syllabus Assignments Scores Course Tools eText Study Area User Settings Part A Producer gas is a type of fuel gas made by passing air or steam through a bed of hot coal or coke. A typical producer gas has the following composition in percent by volume: 8.0 % CO2 ,23.2 % CO 177 % H 2, 1.1 % CH4, and 50.0% N2 What is the density of this gas at 30 °C and 759 mm Hg, in grams per liter? g/L My Answers Give Up Part B What is the partial pressure of CO in this mixture at STP? mmHg My Answers Give Up

Explanation / Answer

A)

Apply Ideal Gas Law,

PV = nRT

where

P = absolute pressure; V = total volume of gas

n = moles of gas

T = absolute Temperature; R = ideal gas constant

D = mass / volume and Molar volume = n/V

MW = molar weight of sample

Then,

PV = nRT; get molar volume

n/V = P/(RT)

get mass -> n = mass/MW

mass/(MW*V) = P/(RT)

D = mass/V

D/MW = P/(RT)

D = P*MW/(RT)

MW avg = MWx1+MW2x2 + MW2x3 = (0.08)(44) + 0.232*28 +0.177*2 + 0.011*16 + 0.50*28 = 24.546

D = 24.546*(759)/(62.4*303)

D = 0.9853 g/L

B)

find P-CO

Ptotal = 759 mm Hg

P-CO = x-CO2 * Ptotal = (0.232)*759 = 176.088 mm Hg

c)

moles of gas --> PV/(RT) = (741*1500)/(62.4*(23+273)) = 60.17

of which

CO = 60.17*0.232 = 13.959

H2 = 0.177*60.17 = 10.65

CH4 = 60.17*0.011= 0.661

mol of O2 required

for CO = 1/2*13.959 = 6.9795

H2 = 1/2*10.65 = 5.325

CH4 = 2*0.661 = 1.322

Total O2 = 6.9795+5.325+1.322 = 13.6265

air = 13.6265/0.21 = 64.888 mol of air

PV = nRT

V = nRT/P = (64.888)(62.4*(23+273))/741

V = 1617.41 L

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