Experiment 8 Pre-Lab Questions Answer all calculation questions to the correct n
ID: 559235 • Letter: E
Question
Experiment 8 Pre-Lab Questions Answer all calculation questions to the correct number of significant figures. 1. What pressure in atmospheres corresponds to 720.3 mm Hg? 2. What temperature in K corresponds to 97 °C? 3. A student performs the experiment and records the following data: Barometric pressure: 741.6 torr Temperature of water bath: 99 °C Volume of flask: 273 mL . Mass of condensed vapor: 0.65 g a. The student calculates the molar mass of the gas to be 2.6 x 10-. What mistake did he make? b. What is the molar mass of the gas? Show your calculations. 4. Why it is not necessary to measure the volume of the unknown liquid that is placed in the flask? 5. Refer to the equation that relates'to the mass of the vapor (w). If either w or T is somehow too large or if either P or V is too small, then M/will be too large. Give an example of a procedural error that would result in obtaining a molar mass value larger than the true value. 59Explanation / Answer
We have,
1
1atm = 760 mm Hg
720.3 mm Hg = 1 atm /760 mm Hg x 720.3 mm Hg = 0.948 atm
2.
K = oC + 273.15
for 97 oC
K = 97 + 273.15 = 370.15K
3.
Molar mass cannot be less than 1g/mol as no element can be lighter than hydrogen atom and hence there is some calculation mistake
We have to use ideal gas equation to find no. of moles
PV = nRT
P = pressure
V = volume
n = no. of moles
R = gas constant
T = temperature in K
1 torr = 1mmHg
741.6 torr = 741.6 /760 x 1 atm = 0.9758 atm
99 oC = 99 + 273.15 = 362.15K
volume = 273 mL = 0.273 L
n = PV/RT = 0.9758 atm x 0.273L / 0.08206atm.L/mol.K x 362.15K = 0.008964 mol
molar mass = mass / moles = 0.65g/ 0.008964 moles = 72.51g/mol
4.
to know the actual volume of gas ,we should know the volume of liquid in the chamber as gas gives the total volume over in the vessel
total gas volume = volume of chamber - volume of liquid present
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