13) What is the Kw of pure water at 50.0°C, if the pH is 6630? 13) A) 5.50 × 10-

Question

13) What is the Kw of pure water at 50.0°C, if the pH is 6630? 13) A) 5.50 × 10-14 B) 2.13 x 10-14 C) 1.00% 10-14 D) 2.34 x 10-7 E) There is not enough information to calculate the Kw. 14) Calculate the concentration of OH in a solution that contains 3.9 10-4 M H30* at 25°C 14) Identify the solution as acidic, basic or neutral. A) 3.9 x 10-4 M, neutral B) 2.7 x 10-2 M, basic C) 2.6 x 10-11 M, acidic D) 2.7 x 10-2 M, acidic E) 2.6 x 10-11 M, basic 15) Calculate the pOH of a solution that contains 3.9 x 10-4 M H30' at 25°C. 15) A) 3.31 B) 4.59 C) 10.59 D) 0.59 E) 9.14 16) Calculate the pH of a solution that contains 2.4 10-5 M H30' at 25°C. 16) A) 4.62 B) 2.40 C) 9.38 D) 4.17 E) 11.60 17) 17) Determine the pH of a 0.023 M HNO3 solution. A) 1.64 B) 2.49 C) 12.36 D) 2.30 E) 3.68 18) Calculate the hydroxide ion concentration in an aqueous solution with a pH of 4.33 at 25°C. 18) A) 6.3 x 10-6 M B) 4.7 x 10-5 M C) 3.8 x 10-5 M D) 2.1 x 10-10 M E) 9.7 x 10-10 M

Explanation / Answer

13)

we have below equation to be used:

pH = -log [H+]

6.63 = -log [H+]

log [H+] = -6.63

[H+] = 10^(-6.63)

[H+] = 2.344*10^-7 M

for water,

[H+] = [OH-]

So,

[OH-] = 2.344*10^-7 M

Use:

Kw = [H+] [OH-]

= (2.344*10^-7)*(2.344*10^-7)

= 5.50*10^-14

Answer: A

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