Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

PLEASE SHOW ALL WORK!! Genotype Number of offspring A,T,G 315 a,t,g 319 A,T,g 10

ID: 55740 • Letter: P

Question

PLEASE SHOW ALL WORK!!

Genotype

Number of offspring

A,T,G

315

a,t,g

319

A,T,g

100

A,t,G

70

A,t,g

19

a,T,G

15

a,t,G

96

a,T,g

66

a What are the parental chromosomes (i.e. no recombination has occurred)?

b What is the linear order of the three genes (i.e. which gene is in the middle)? How do you know this?

c Create a linear map of the genes A, T, and G. Include the centiMorgan (cM) distance between each gene.


Genotype

Number of offspring

A,T,G

315

a,t,g

319

A,T,g

100

A,t,G

70

A,t,g

19

a,T,G

15

a,t,G

96

a,T,g

66

Explanation / Answer

a) The parental chromosome is ATG and atg.

b) ATG - 315 ;ATg - 100 ; aTG - 15; aTg -66; AtG-70; Atg - 19; atG - 96 and atg - 319.

Single cross over class are aTG-15, aTg-66, AtG-70 and Atg-19.

The total recombinant offspring are (15+66+70+19) = 170. Total number of offspring - 1000. The recombinant between A and T is 170, Hence distance = 170/1000 X 100 = 17 LMU between A and T.

Recombinants between T and G ATg-100; atG -96, aTg-66 and AtG-70

Distance between t and g = 332/1000 x 100 = 33.2

Distance between t and g is 33.2 LMU

Distance between A and G is 33.2 + 19 = 50.2.

c, The genes are in the order of ATG, the distance between AT = 17 cM and TG = 33.2 cM and A and G = 50.2 cM.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote