Boyle\'s Law:Pressure.Volume Relationship in Gases fit curve c. A best-f exponen

ID: 557320 • Letter: B

Question

Boyle's Law:Pressure.Volume Relationship in Gases fit curve c. A best-f exponent and clicky itlagain. When the curve has a good fit with the data points, then t a copy of the graph, with the graph of pressure vs volume and its best-fit curve 9. With the best-fit curve still displayed, peoceed directly to the Processing the Data section. DATA AND CALCULATIONS Volume (mL) PressurC atm or PV PROCESSING THE DATA (ANSWER THE QUESTIONS IN THE SPACE PROVIDED) 1. With the best-fit curve still displayed, choose Interpolate from the Analyze menu. A vertical cursor now appears on the graph. The cursor's volume and pressure coordinates are displayed in the floating box. Move the cursor along the regression line until the volume value is 5.0 mL. Note the corresponding pressure value. Now move the cursor until the volume value is doubled (10.0 mL). What does your data show happens to the pressure when the volume is doubled? Show the pressure values in your answer 2. Using the same technique as in Question 1, what does your data show happens to the pressure if the volume is halved from 20.0 mL to 10.0 mL? Show the pressure values in your answer. if the volume is tripled from 5.0 mL, to 15.0 mL? Show the pressure values in your answer. Chemistry with Computers 6-3

Explanation / Answer

Volume

Pressure (atm)

Constant P/V

Constant PV

5.8

192.20

33.14

1114.76

7.8

145.26

18.62

1133.02

9.8

115.13

11.74

1128.27

11.8

95.03

8.05

1121.35

13.8

88.88

6.44

1226.54

15.8

70.11

4.44

1107.31

17.8

62.37

3.50

1110.19

1) When volume is doubled from 5ml to 10 ml, pressure decreased from 224.70 atm to 112.20 atm.

2) When volume is halved from 20ml to 10 ml, pressure increased from 55.74 atm to 112.20 atm

1) When volume is tripled from 5ml to 15 ml, pressure decreased from 223.50 atm to 74.32 atm.

4) In question no.1 when volume is doubled from 5ml to 10 ml, pressure decreased from 224.70 atm to 112.20 atm

5) Volume increased to 40 ml

When volume is = 20ml, then pressure is= atm 55.74

Volume increased to 40 ml = P ?

P =( 20ml x 55.74 atm)/40 ml = 27.87 atm

6) Volume decreased to 2.5 ml, pressure will increased

P=( 20ml x 55.74 atm)/2.5 ml = 445.92 atm

7) The temperature remains constant in this experiment.

9) Value of P/V is not constant, so there is no direct relationship between P and V

Value of P x V is relatively constant, so there is indirect relationship between P and V

V 1/p (at constant temperature)

or PV = k (k is proportionality constant)

10)

PV = K at constant temperature.

Boyles’ Law states, if temperature remains constant, then the volume of a fixed amount of gas is inversely proportional to its pressure.