131 Name Locker Number_ Date, Piease print last name firet PRELIMINARY EXERCISES

Question

131 Name Locker Number_ Date, Piease print last name firet PRELIMINARY EXERCISES: Experiment 9 Analysis of a KCio-KCI Mixture 1. Aluminum powder can burn in pure oxvgen to form aluminum oxide, Al,o,. The balanced equation is: Write numbers in the small blanks to identify four mole ratios that exist in this balanced equation. Y ou may want to refer to the Chemical Arithmetic-Equations exercises: mol Al mol Al,O mol O2 mol Al,O, mol Al mol Alo -mol O2 -mol Al ferring to the balanced equation in question 1, what mass of aluminum is required to just completely react with 96.0 g of O2? The molar masses are: Al = 27.0 g O2 = 32.0 g Please show your calculations below. Mass of Al = How many grams of oxygen, O2, would be produced in the complete decomposition of 10.0 g of KCIO,? The maolar masses are: O2 = 32.0 & KCIO3-122.6 g. The balanced equation is: 3. MnO, Mass of 0,

Explanation / Answer

Q1.

4/3 = 1.333 mol of Al/O2

2/4 = 0.5 mol of Al2O3/Al

3/2 = 1.5 mol of O2 / Al2O3

4/2 = 2 mol of Al/Al2O3

Q2

mol of O2 = mass/MW = 96/32 = 3 mol of O2 required

then...

4/3*96/32 = 4 mol of Al will be needed

mass = mol*MW = 4*27 = 108 g of Al

Q3

mass of O2 produced from

mol of KClO3 = mass/MW = 10/(122.6) = 0.0815

mol of O2 --> 3/"*0.0815 = 0.12225 mol of O2

mass = mol*MW =0.12225*32 = 3.912 g of O2

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