2 out of 2 attempts Check my work Be sure to answer all parts. In an electron mi

Question

2 out of 2 attempts Check my work Be sure to answer all parts. In an electron microscope, electrons are accelerated by passing them through a voltage difference. The kinetic energy thus acquired by the electrons is equal to the voltage times the charge on the electron. Thus, a voltage difference of I volt imparts a kinetic energy of 1.602 x 10-19 volt- coulomb or 1.602 x 10-19 J. Calculate the wavelength associated with electrons accelerated by 5.50 x 10 volts. 226-1 x 10:10 pm Enter your answer in scientific notation.) View Details of Last Check Answer a Reférences

Explanation / Answer

1V = 1.602*10^-19 eV

change to energy

E = (5.5*10^3)*(1.602*10^-19)

E = 8.811*10^-16 J/electron

then..

E = hc/WL

For the wavelength:

WL = h c / E

h = Planck Constant = 6.626*10^-34 J s

c = speed of particle (i.e. light) = 3*10^8 m/s

E = energy per particle J/photon

WL = wavelength in meters

WL = hc/W

WL = (6.626*10^-34)(3*10^8)/(8.811*10^-16)

WL = 2.256*10^-10 m

WL = 225.6 pm

WL = 2.25*10^2 pm

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