2 mathd.com/student/PlayerHomeworkaspxthomeworkad-4703022208questionld-1 MATH 11

Question

2 mathd.com/student/PlayerHomeworkaspxthomeworkad-4703022208questionld-1 MATH 111 College Algebra Online Spring 2018 Homework: Section 3.2 Homework Score: 0 of 1 pt 3.2.66 A toy rocket is launched from the top of a building 91 feet tall at an initial velocity of 227 feet per second a) Give the function that describes the height of the rocket in terms of time t b) Determine the time at which the rocket reaches its maximum height, and the maximum height in feet c) For what time interval will the rocket be more than 713 feet above ground level? d) After how many seconds will it hit the ground? a) The function that describes the height of the rocket in terms of t is st)- 3

Explanation / Answer

a) function is

s(t) = -16t^2 + 227 t + 91

b) the time when rocket reaches maximum height is

t = -227 / 2(-16)

t = 7.094 second

maximum height is

y = -16(7.094)^2 + 227 (7.094) + 91

= 896.141 feet

c) plugging y = 713

713 =  -16t^2 + 227 t + 91

t = 3.71 , 10.48 seconds

d) it will hit the ground

0 =  -16t^2 + 227 t + 91  

after 14,578 seconds

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.