Your name: Questions (1)-(X) (4pts each) () What is the final concentration if 5

Question

Your name: Questions (1)-(X) (4pts each) () What is the final concentration if 55.0 mL of 2.50 M glucose solution is diluted to a volume of 500.0 mL? (u) Copper reacts with diluted nitric acid according to the following balanced equation. If Copper wire weighing 1.50 g is completely dissolved in a small amount of nitric acid and the resultant solution is diluted to 100.0mL of water, what is the molarity(M Jof Cu(NO3)2? 3Cu (s) +8HNO3(aq) 3Cu(NO3)2(aq) + 2NO(g) + 4H20 (1) Balanceandcompletethefollowing precipitation reactions and write balanced net ionic equation for each of the following reaction: () a) AgNO3 (aq) Na2SO4 (aq) + Net ionic equation: b) K:PO4 (aq) Sr(NO3)2 (aq) Net ionic equation:

Explanation / Answer

I)

We need to apply dilution law, which is based on the mass conservation principle

initial mass = final mass

this apply for moles as weel ( if there is no reaction, which is the case )

mol of A initially = mol of A finally

or, for this case

moles of A in stock = moles of A in diluted solution

Recall that

mol of A = Molarity of A * Volume of A

then

moles of A in stock = moles of A in diluted solution

Molarity of A in stock * Volume of A in stock = Molarity of A in diluted solution* Volume of A in diluted solution

Now, substitute known data

C1*V1 = C2*V2

C2 = C1*V1/V2

C2 = 2.5*55/500

C2 = 0.275 M

II)

mol of Copper = mass/MW = 1.5/63.5 = 0.02362

M = mol/V

M = 0.02362 / 0.1 = 0.2362 M of Cu(NO3)2

III)

net ionic includes only reacting species

a)

2Ag+(aq) + SO4-2(aq) = Ag2SO4(s)

b)

3Sr+2(aq) + 2PO4-3(aq) --> Sr3(PO4)2(s)

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