Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

I am to conduct an experiment based on methyl ester methionine. There\'s an expe

ID: 554024 • Letter: I

Question

I am to conduct an experiment based on methyl ester methionine. There's an experimental procedure that I am to follow. The procedure states that they used a 1 to 1 equivalent, 5.9 grams of 33mM methyl ester of Methionine. I am to follow this except I have l-methyl ester of methionine hcl that is 98% (assuming 98 g of l-methyl ester methionine hcl over 100 g of solution). How do I figure out the amount of l-methyl esther methionine hcl I need in order to match the 8.7 grams of 33mM for the methyl ester methionine used in the procedure? I need the answer in grams.

My answer was 6.45 grams of l-methyl ester methionine hcl. Did I approach this correctly? Please let me know if more information is needed or if clarification is needed.

More information- Molar mass for methyl ester of methionine and l-methyl ester of methionine seem to be 199.70 g/mol.

The whole procedure- " acid chloride of palmitic acid, C15H31COOH ( 1 equir, 8.7 grams, 30 mM) was dissolved in dry DCM. To this solution methyl ester of Methionine (1.1 equiv, 5.9 g, 33 mM) was added followed by pryridine (1.1 equiv.)"

33 mmol methyl ester of methionine 10-3 1 mol l-methyl ester Methionine 199.70 g l-methyl ester methionine 98 g l-methyl ester methionine L of solution m 1 mol methyl ester of methionine 1 mol of -methyl ester methionine 100 g solution

Explanation / Answer

Molar mass of L- methionine methyl ester hydrochloride is 199.70 grams/ mole

Molar mass of HCl is = 36.5 grams/ mole

So, in 199.70 grams of L- methionine methyl ester hydrochloride, there is (199.70-36.50) grams = 163.2 grams of L- methionine methyl este

So, you may say that: 163.2 grams of L- methionine methyl este is present in 199.70 grams of L- methionine methyl ester hydrochloride

You have to use 5.9 grams of L- methionine methyl ester which is present in (199.7* 5.9)/ 163.2 grams = 7.22 grams of L- methionine methyl ester hydrochloride

The answer is : 7.22 grams of L- methionine methyl ester hydrochloride

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote