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ent/takeCovalentActivity.do?locator-assignment-take&itakeAssignmentSessionlocato

ID: 553952 • Letter: E

Question

ent/takeCovalentActivity.do?locator-assignment-take&itakeAssignmentSessionlocators; assignment-take Splitting of a signal in a proton NMR spectrum / signal. Predict the number of lines exhibited by hydrogens at the labeled positions constants are equal.) tells us the number of chemically non-equivalent hydrogens in the impsediate vicinity of i the hydrogen giving the in a first-order NMR spectrum. (Make the approximation that all coupling / 1) The number of lines exhibited by hydrogens) a is The number of lines exhibited by hydrogen(s) b is The number of lines exhibited by hydrogen(s) e is 2) a c The number of lines exhibited by hydrogens) The mumber of lines exhibited by bydrogets)b s The number of lines exhibited by hydrogen(s) e is Submit Answer Retry Entire Group 6 more group attempts remaining Previous Next Email Instructor Save and

Explanation / Answer

To get this answer you must count the number of neighbor protons and apply number of lines = n + 1

1.

a : the neighbor of this carbon has only 1 hydrogen so n = 1, number of lines = 2

b: neighbor from the left has 3 hydrogens, neighbor from the right 2 hydrogens, number of lines 3 + 2 + 1 = 6

c: neighbor from the left has 1 hydrogen, neighbor from the right 3 hydrogens, number of lines 1 + 3 + 1 = 5

2.

a: neighbor has only 1 hydrogen, number of lines = 1 + 1 = 2 lines

b: neighbor from the top has 3, from the left has 2, from the right has 3: 3 + 2 + 3 + 1 = 9 lines

c: neighbor from the left has no hydrogens, neighbor from the right has 1 hydrogen, 1 + 1 = 2 lines

3.

a: neighbor has 2 hydrogens, number of lines 2 + 1 = 3 lines

b: neighbor from the right has 3, from the left has 2, lines = 3 + 2 + 1 = 6 lines

c: neighbor from the left has 2 , from the right has 2 , number of lines = 2 + 2 + 1 = 5 lines

4.

a: the CN group has no hydroges, the neighbor from the left has 2 hydrogens: lines = 2 + 1 = 3

b: from the left we have 3 hydrogens, from the right we have 1, then lines = 3 + 1 + 1 = 5

c: the only neighbor is the carbon from the right which has 2 hydrogens, lines = 2 + 1 = 3