R Cengage XY OVLv2 Online teaching X attaa - Ox t h co cvgcengagenowcom/filn/tak
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R Cengage XY OVLv2 Online teaching X attaa - Ox t h co cvgcengagenowcom/filn/takeAssignment/takeCovalentActivitydo?locator-assignment-take&takeAssignmentSessionlocator;=assignment-take Chapter 12: Mastery Review Topics 1. Determine Use the References to access important values if needed for this question. Question Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M = 96.058. Question Question Exact Masses of the most Abundant Isotope of Selected Elements 2 Mass S Isotope Natural abundance (%) Exact mass 3 Infrared “H 99.985 1.008 4. Infrared 12,000 12c 98.90 14N 99.63 16o 99.76 14.003 5. Determi, 15.995 Molecular formula C6H (In the order CHNO, with no subscripts) An error has been detected in your answer. Check for typos, miscalculations etc. before submitting your answer Submit Answer Retry Entire Group 9 more group attempts remaining Progress 15 groups Due Nov 2 at 12:00 PM Previous Show Hint Finish Assignment Email Instructor Save and Exit Cengage Learning Cengage Technical Support 12:06 AM HO Type here to search 0 o G JR WDo 11/2/2017Explanation / Answer
Answer:
MW of unknown = 96
Even mass indicates either absence of N or even number of N atoms present.
1) Determination of Hydrocarbon formula by Rule of 13.
Dividing MW 96 by 13 we get quotient = 7 and remainder = 5 hence the hydrocarbon formula is C7H12.
The unknown compound expected to be containing N & O also so we need to adjust Hydrocarbon formula accordingly.
To adjust 2 N (even N neccessarily) we need to cut hydrocarbon formula by mass 28 (2 N mass 14x2 =2)
which is equal to removal of 2 CH2 groups i.e. C2H4 and to adjust 1O we need to remove CH4 (16 mass for 1O)
Toally we need to remove C3H8 part from hydrocarbon formula
So
Possible MF : C7H12 - C3H8 + (2N) + (1O) = C4H4N2O.
Possible MF is thus C4H4N2O.
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